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回答No.1
z=(x-y)/(x+y)=1-2y/(x+y)=2x/(x+y)-1 ∂z/∂x=2y/(x+y)^2, ∂z/∂y= -2x/(x+y)^2 dz=(∂z/∂x)dx+(∂z/∂y)dy = 2(ydx-xdy)/(x+y)^2 ... (Ans.)
z=(x-y)/(x+y)=1-2y/(x+y)=2x/(x+y)-1 ∂z/∂x=2y/(x+y)^2, ∂z/∂y= -2x/(x+y)^2 dz=(∂z/∂x)dx+(∂z/∂y)dy = 2(ydx-xdy)/(x+y)^2 ... (Ans.)