単語検索プログラム
論文の中から入力された単語を探し出し、その単語が含まれる行を表示させるというプログラムを作りたいのですが、うまくいきません。下に私が作ったプログラムを載せておくのでどこをどうすればいいのかを指摘してください。お願いします。
#include <stdio.h>
#include <string.h>
#define NUM_LINE 26
#define NUM_COL 128
int main(void){
char text[NUM_LINE][NUM_COL]={
" Four score and seven years ago our fathers brought forth",
"on this continent, a new nation, conceived in Liberty, and",
"dedicated to the proposition that all men are created equal.",
" Now we are engaged in a great civil war, testing whether",
"that nation, or any nation so conceived and so dedicated,",
"can long endure. We are met on a great battle-field of that",
"war. We have come to dedicate a portion of that field, as a",
"final resting place for those who here gave their lives that",
"that nation might live. It is altogether fitting and proper",
"that we should do this.",
" But, in a larger sense, we can not dedicate -- we can not",
"consecrate -- we can not hallow -- this ground. The brave",
"men, living and dead, who struggled here, have consecrated",
"it, far above our poor power to add or detract. The world",
"will little note, nor long remember what we say here, but",
"it can never forget what they did here. It is for us the",
"living, rather, to be dedicated here to the unfinished work",
"which they who fought here have thus far so nobly",
"advanced. It is rather for us to be here dedicated to the",
"great task remaining before us -- that from these honored",
"dead we take increased devotion to that cause for which",
"they gave the last full measure of devotion -- that we here",
"highly resolve that these dead shall not have died in",
"vain -- that this nation, under God, shall have a new birth",
"of freedom -- and that government of the people, by the",
"people, for the people, shall not perish from the earth."
};
char line[100];
int i, j, k, length;
printf("> Search for ");
fgets(line, sizeof(line), stdin);
for(i = 0; line[i] != '\n'; i++){
length++;
}
for(k = 0; k < length; k++){
for(i = 0; i < NUM_LINE; i++){
for(j = 0; j < NUM_COL; j++){
if(text[i][j + k] == line[k]){
}
}
printf("%d: %s\n", i, text[i]);
}
printf("\n");
}
return 0;
}
お礼
大変参考になりました。ありがとうございました。